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CBSE Class 10 Maths Chapter 13: Statistics Notes

📖 Chapter Notes ✏️ NCERT Solutions 📥 PDF Notes

1. Mean of Grouped Data (Direct Method)

The Mean (average) of grouped frequency distribution data using the standard Direct Method is calculated as:

$$\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$$

Where $x_i = \text{class mark} = \frac{\text{Upper Limit} + \text{Lower Limit}}{2}$, and $f_i = \text{frequency}$.

2. Mode of Grouped Data

The Mode represents the value that appears most frequently. For grouped data, find the Modal Class (the class interval with the highest frequency) and use:

$$\text{Mode} = l + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \right) \times h$$

• $l = \text{lower limit of modal class}$
• $f_1 = \text{frequency of modal class}$
• $f_0 = \text{frequency of preceding class}$
• $f_2 = \text{frequency of succeeding class}$
• $h = \text{class interval width}$

3. Median of Grouped Data

The Median represents the middle-most score. Find the Median Class where the cumulative frequency ($cf$) crosses the value of $N/2$:

$$\text{Median} = l + \left( \frac{\frac{N}{2} - cf}{f} \right) \times h$$
CBSE MCQ Lifesaver Rule

Empirical Relationship Formula: If a 1-mark question gives you any two parameters out of mean, median, or mode and asks for the third, do not calculate tables! Just use this golden rule:
$$3 \times \text{Median} = \text{Mode} + 2 \times \text{Mean}$$


✏️ Complete NCERT Solutions Class 10 Statistics

Exercise 13.1
Q1. Given $\sum f_i x_i = 132$ and $\sum f_i = 20$ for a dataset, calculate the Mean.
Step 1: Set up the direct method formula
$\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$
Step 2: Substitute and compute
$\bar{x} = \frac{132}{20} = \mathbf{6.6}$